R
riske
Guest
No, torque is rotational force per lb/ft and BHP is power per second. its actually quite simple once u get passed the confusing stuff...lol. Im still in the confusing part. read through the puma link above.
Not bad Young'nsnoon said:I must be doing something right as my figures are close to being the same......
350 BHP and 344 torque!
Interesting read.
All is explained :lol:fubar andy said:yet when I looked at my lbft it was much lower than I expected, hence my query!
Make sense now :thumb:The best way to improve torque is to either apply a greater force to the piston, reduce the frictional losses between the piston and the cylinder / conrod / crank or increase the crank throw so that the same force acts over a longer lever.
Increasing force on the piston is the usual method used i.e. increasing boost, cams, bigger turbos, ported heads etc..
Reducing friction comes as a result of coatings applied to piston skirts, conrod and crank bearings, choice of oils etc..
Using a longer crank throw applies to stroker kits. Probably best if I use a bit of an example to describe this one though. The std Evo engine has a stroke of 88mm. This means that the distance between top dead centre and bottom dead centre is 88mm. Now thinking about it logically, this means that the radius of the circle that the conrod travels around is 44mm. This 44mm is called the crank 'throw'.
Now say we have an engine which is producing a downward force of 2083 lbs (you'll see why it's an odd number in a minute ) then we have a torque being produced at the crankshaft of:
44mm = 0.144 ft radius
and
Torque = force * distance = 2083 * 0.144 = 300 ft-lbs
Now say we keep the engine developing the same 2083lbs of force i.e. same boost level, airflow etc... but we put in a 100mm diameter crank which has a 50mm throw then that same 2083 lbs of force develops a torque of:
50mm = 0.164 ft
therefore
Torque = 2083 * 0.164 = 342 ft-lbs
So you can keep the boost level the same and put the same force on the piston but you get an increase in torque due to the extra diameter of the crankshaft.